Step 1: Understanding the Concept:
When a mixture of an aryl halide and an alkyl halide is treated with sodium metal in the presence of dry ether, an alkyl-substituted aromatic compound is formed. This reaction is a modified version of the Wurtz reaction.
Step 2: Key Formula or Approach:
The general representation of Wurtz-Fittig reaction is:
\[ \text{Ar-X} + 2\text{Na} + \text{R-X} \xrightarrow{\text{dry ether}} \text{Ar-R} + 2\text{NaX} \]
Step 3: Detailed Explanation:
In the given problem, bromobenzene (\(\text{C}_6\text{H}_5\text{Br}\)) is the aryl halide and bromomethane (\(\text{CH}_3\text{Br}\)) is the alkyl halide.
The reaction can be written as:
\[ \text{C}_6\text{H}_5\text{Br} + 2\text{Na} + \text{CH}_3\text{Br} \xrightarrow{\text{dry ether}} \text{C}_6\text{H}_5\text{-CH}_3 \text{ (Toluene)} + 2\text{NaBr} \]
- Wurtz reaction: Involves two alkyl halides to form alkanes.
- Fittig reaction: Involves two aryl halides to form diphenyl.
- Friedel-Crafts reaction: Involves alkylation/acylation using \(\text{AlCl}_3\) catalyst.
Thus, the specific combination of one aryl and one alkyl halide with Sodium is Wurtz-Fittig.
Step 4: Final Answer:
The reaction is the Wurtz-Fittig reaction.