Question:medium
The ratio of the weight of a body at a height of \(\dfrac{R}{10}\) from the surface of the earth to that at a depth of \(\dfrac{R}{10}\) is \((R\) is radius of earth\()\)
The ratio of the weight of a body at a height of \(\dfrac{R}{10}\) from the surface of the earth to that at a depth of \(\dfrac{R}{10}\) is \((R\) is radius of earth\()\)
Show Hint
Use:
\[
g_h \approx g\left(1-\frac{2h}{R}\right), \qquad g_d=g\left(1-\frac{d}{R}\right)
\]
for small heights and depths.
Updated On: Apr 29, 2026
- \(4:5\)
- \(1:1\)
- \(9:8\)
- \(2:3\)
- \(8:9\)
Show Solution
The Correct Option is
Solution and Explanation
Was this answer helpful?
0
Top Questions on Newtons law of gravitation
- What is the gravitational force between two 5 kg masses placed 2 meters apart? (Take \( G = 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \))
- MHT CET - 2025
- Physics
- Newtons law of gravitation
- Two bodies of masses \( m_1 = 5 \, \text{kg} \) and \( m_2 = 10 \, \text{kg} \) are placed 2 meters apart. What is the gravitational force between them?
- MHT CET - 2025
- Physics
- Newtons law of gravitation
- A 90 kg body placed at \( 2R \) distance from the surface of the earth experiences gravitational pull of:
(\( R \) = Radius of Earth, \( g = 10 \, \text{ms}^{-2} \)).- JEE Main - 2024
- Physics
- Newtons law of gravitation
- The weight of an object measured on the surface of earth is 300 N. What will be the weight of the same object at depth R/4 inside the earth? (Given R = Radius of earth)
- Want to practice more? Try solving extra ecology questions todayView All Questions
