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The ratio of the surface area of the nuclei \(_{52}\text{Te}^{125}\) to that of \(_{13}\text{Al}^{27}\) is
The ratio of the surface area of the nuclei \(_{52}\text{Te}^{125}\) to that of \(_{13}\text{Al}^{27}\) is
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Nuclear physics ratios usually involve cube roots ($1/3$ for Radius) or mass numbers directly ($1$ for Volume). Surface area is the "middle ground" using the power of $2/3$.
Updated On: May 6, 2026
- \(\frac{5}{3}\)
- \(\frac{125}{17}\)
- \(\frac{1}{4}\)
- \(\frac{25}{9}\)
- \(\frac{3}{5}\)
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The Correct Option is D
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