Question:medium

The ratio of the maximum shear stress and the average shear stress in a circular section is

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Maximum shear stress: \[ \boxed{ \begin{aligned} \text{Rectangle} &: \tau_{\max}=1.5\,\tau_{\text{avg}} \text{Circle} &: \tau_{\max}=\frac{4}{3}\tau_{\text{avg}} \end{aligned} } \]
Updated On: Jul 24, 2026
  • \(\dfrac{3}{4}\)
  • \(\dfrac{4}{3}\)
  • \(\dfrac{2}{3}\)
  • \(\dfrac{3}{2}\)
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The Correct Option is B

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