Question

The ratio of the density of oxygen nucleus \((_8^{16}\text{O})\) and helium nucleus \((_2^4\text{He})\) is

• A. \(1:1\)
• B. \(2:1\)
• C. \(4:1\)
• D. \(8:1\)

Hint:

Nuclear density does not depend on the mass number.

Answer 1

The Correct Option is A

Step 1: Compute
$\rho = \frac{Am_p}{\frac43\pi R_0^3A} = \frac{3m_p}{4\pi R_0^3}$, independent of $A$. Option (A).

Final Answer:
1:1. \[ \boxed{\text{(A)}\ 1:1} \]