Question:medium

The ratio of is given as \( \frac{E{\lambda}_1 b_2}{E{\lambda}_1 b_1} \) is given as:

Show Hint

When dealing with thermal ratios, the relationship between temperature and thermal properties often involves powers of the temperature ratio.
Updated On: Feb 18, 2026
  • \( \left(\frac{T_2}{T_1}\right)^5 \)
  • \( \left(\frac{T_2}{T_1}\right)^4 \)
  • \( \left(\frac{T_2}{T_1}\right)^3 \)
  • \( \left(\frac{T_2}{T_1}\right)^2 \)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Ratio Analysis.
The ratio \( \frac{E{\lambda}_1 b_2}{E{\lambda}_1 b_1} \), dependent on the temperature ratio \( \frac{T_2}{T_1} \), usually represents a specific heat or thermal conductivity ratio.Step 2: Final Result.
This ratio equals \( \left( \frac{T_2}{T_1} \right)^4 \), based on thermodynamic principles. Final Answer: \[ \boxed{\left( \frac{T_2}{T_1} \right)^4} \]
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