Question:medium

The random process \(X(t)=A\cos(\omega_0 t+\theta)\) is wide-sense stationary, where \(A\) and \(\omega_0\) are constants and \(\theta\) is a uniformly distributed random variable on the interval \((0,2\pi)\). Then the mean value is

Show Hint

A sinusoidal random process with uniformly distributed phase over \((0,2\pi)\) always has zero mean.

Updated On: Jun 25, 2026

Show Solution

Was this answer helpful?

A periodic signal \(x(t)\) of period \(T_0\) is given by \( x(t) = \begin{cases} 1, & |t|<T_1 \\ 0, & T_1<|t|<\frac{T_0}{2} \end{cases} \). The dc component of \(x(t)\) is
- CUET (PG) - 2025
- Electronics Engineering
- Signals and Systems
View Solution

Signals and their Fourier Transforms are given in the table below. Match LIST-I with LIST-II and choose the correct answer.

LIST-I	LIST-II
A. \( e^{-at}u(t), a>0 \)	I. \( \pi[\delta(\omega - \omega_0) + \delta(\omega + \omega_0)] \)
B. \( \cos \omega_0 t \)	II. \( \frac{1}{j\omega + a} \)
C. \( \sin \omega_0 t \)	III. \( \frac{1}{(j\omega + a)^2} \)
D. \( te^{-at}u(t), a>0 \)	IV. \( -j\pi[\delta(\omega - \omega_0) - \delta(\omega + \omega_0)] \)