Step 1: Temperature:
$\frac{V_2}{V_1} = \frac{T_2}{T_1} = 3$, so $T_2 = 819$ K.
Step 2: Speed:
$v_{rms}^2 \propto T$, so tripling $T$ multiplies the speed by $\sqrt3$.
Final Answer:
The answer is $819$ K and $\sqrt{3}\,u$ m/s, option (C).
\[ \boxed{819\ \text{K},\ \sqrt{3}\,u} \]