Question:medium
The r.m.s current of an alternating current given by $i = 4\sqrt{2}\sin \omega t + 3\sqrt{2}\cos \omega t$ is:
The r.m.s current of an alternating current given by $i = 4\sqrt{2}\sin \omega t + 3\sqrt{2}\cos \omega t$ is:
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Combine sine and cosine using $\sqrt{a^2 + b^2}$.
Updated On: Apr 24, 2026
- $5A$
- $3A$
- $5\sqrt{2}A$
- $2.5A$
- $7\sqrt{2}A$
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The Correct Option is A
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