Question:easy

The product of the H.C.F. and L.C.M. of two numbers 50 and 20 is :

Show Hint

For any two positive numbers, you do not need to calculate their H.C.F. and L.C.M. separately to find their product.
Directly multiplying the two given numbers is much faster and saves valuable exam time.
Note that this property only holds true for two numbers and cannot be directly generalized to three or more numbers.
Updated On: Jul 7, 2026
  • 100
  • 1000
  • 50
  • 20
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understand what is being asked.
We are given two numbers, 50 and 20, and asked to find the product of their H.C.F. and L.C.M. Instead of using the shortcut property directly, let us find the H.C.F. and L.C.M. separately using the division method, and then multiply them.

Step 2: Find the H.C.F. using Euclid's division algorithm.
Divide the larger number by the smaller number and keep dividing the divisor by the remainder until the remainder becomes 0.
Divide 50 by 20: $50 = 20 \times 2 + 10$
Divide 20 by the remainder 10: $20 = 10 \times 2 + 0$
Since the remainder is now 0, the last divisor is the H.C.F.
\[ \text{H.C.F.}(50, 20) = 10 \]
Step 3: Find the L.C.M. using the H.C.F.
For any two numbers $a$ and $b$, the product of the numbers equals the product of their H.C.F. and L.C.M. This gives a formula to get the L.C.M. once the H.C.F. is known:
\[ \text{L.C.M.} = \frac{a \times b}{\text{H.C.F.}} \]
Substitute the values:
\[ \text{L.C.M.}(50, 20) = \frac{50 \times 20}{10} = \frac{1000}{10} = 100 \]
Step 4: Multiply the H.C.F. and L.C.M.
\[ \text{H.C.F.} \times \text{L.C.M.} = 10 \times 100 = 1000 \]
This confirms the required product without ever multiplying 50 and 20 directly.

Final Answer:
The product of the H.C.F. and L.C.M. of 50 and 20 is 1000.
\[ \boxed{1000} \]
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