Question:medium

The probability density function of a continuous random variable is \[ f(x)= \begin{cases} \dfrac35 e^{-3x/5}, & x>0 \\ 0, & x\le0 \end{cases} \] The mean of the distribution is

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For exponential distribution \[ f(x)=\lambda e^{-\lambda x}, \] remember instantly: \[ \text{Mean}=\frac1\lambda, \qquad \text{Variance}=\frac1{\lambda^2}. \]
Updated On: Jun 25, 2026
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The Correct Option is B

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