Question:medium
The pressure inside a mercury drop of diameter 2 mm is (Surface tension of mercury $= 0.5 Nm^{-1}$ and atmospheric pressure $= 10^5$ Pa)
The pressure inside a mercury drop of diameter 2 mm is (Surface tension of mercury $= 0.5 Nm^{-1}$ and atmospheric pressure $= 10^5$ Pa)
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Drop vs Bubble:
- Liquid Drop (in air): 1 Surface $\rightarrow \Delta P = 2T/R$
- Soap Bubble (in air): 2 Surfaces $\rightarrow \Delta P = 4T/R$
- Air Bubble (in liquid): 1 Surface $\rightarrow \Delta P = 2T/R$
Updated On: Mar 31, 2026
- $1.020 \times 10^5$ Pa
- $1.005 \times 10^5$ Pa
- $1.100 \times 10^5$ Pa
- $1.010 \times 10^5$ Pa
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The Correct Option is D
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