Question:medium

The position '$x$' of a particle varies with a time as $x = at^2 - bt^3$ where '$a$' and '$b$' are constants. The acceleration of the particle will be zero at}

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Acceleration is the second derivative of position ($d^2x/dt^2$). Always differentiate carefully with power rule.
Updated On: Apr 28, 2026
  • \frac{2a}{3b}
  • \frac{a}{b}
  • \frac{a}{3b}
  • zero
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The Correct Option is A

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