The position vectors of the points $A$ and $B$ are $\vec{a} = 2\hat{i} - \lambda \hat{j} + 5\hat{k}$ and $\vec{b} = \mu \hat{i} + 7\hat{j} + 3\hat{k}$ respectively. If the position vector of the mid-point of the line segment $AB$ is $\vec{c} = 3\hat{i} + 2\hat{j} + 4\hat{k}$, then the value of $\lambda + \mu$ is equal to
Show Hint
For midpoint vector problems, simply add corresponding components of the endpoint vectors and divide by two. It is identical to the midpoint formula in coordinate geometry.
Step 1: Understanding the Concept:
The position vector of the midpoint of a line segment connecting two points \(\vec{a}\) and \(\vec{b}\) is the average of their position vectors: \(\vec{c} = \frac{\vec{a} + \vec{b}}{2}\). Step 2: Key Formula or Approach:
Equate the \(i\), \(j\), and \(k\) components of \(\frac{\vec{a} + \vec{b}}{2}\) to the corresponding components of \(\vec{c}\). Step 3: Detailed Explanation:
The midpoint vector is:
\[ \frac{(2 + \mu)\hat{i} + (-\lambda + 7)\hat{j} + (5 + 3)\hat{k}}{2} = 3\hat{i} + 2\hat{j} + 4\hat{k} \]
Equate the \(\hat{i}\) components:
\[ \frac{2 + \mu}{2} = 3 \implies 2 + \mu = 6 \implies \mu = 4 \]
Equate the \(\hat{j}\) components:
\[ \frac{-\lambda + 7}{2} = 2 \implies -\lambda + 7 = 4 \implies \lambda = 3 \]
Check the \(\hat{k}\) component just to be sure: \(\frac{5 + 3}{2} = 4\), which is correct.
We need to find \(\lambda + \mu\):
\[ \lambda + \mu = 3 + 4 = 7 \]
Step 4: Final Answer:
The value of \(\lambda + \mu\) is 7.