The position vector of a particle is $\overset{⃗}{r} = acosωt\hat{i}+asinωt\hat{j}$. Calculate the angle between its position vector and the velocity vector.
($cos0 = 1,cos90 = 0,cos60 = 0.5,sin30 = 0.5,sin0 = 0$)

Question

A ball is thrown vertically upwards with an initial velocity of $ 20 \, \text{m/s} $. How high will the ball rise? (Take $ g = 10 \, \text{m/s}^2 $)

Answer 1

Step 1: Use geometry
The path is a circle of radius $a$. The velocity of circular motion is along the tangent, and a tangent is always perpendicular to the radius. So $90^{\circ}$.

Final Answer:
Option (C). \[ \boxed{\text{(C)}} \]

The position vector of a particle is \(\overset{⃗}{r} = acosωt\hat{i}+asinωt\hat{j}\). Calculate the angle between its position vector and the velocity vector.
(\(cos0 = 1,cos90 = 0,cos60 = 0.5,sin30 = 0.5,sin0 = 0\))

Show Hint

The Correct Option is C

Solution and Explanation

Top Questions on Motion in a plane

Questions Asked in MHT CET exam

The position vector of a particle is \(\overset{⃗}{r} = acosωt\hat{i}+asinωt\hat{j}\). Calculate the angle between its position vector and the velocity vector.(\(cos0 = 1,cos90 = 0,cos60 = 0.5,sin30 = 0.5,sin0 = 0\))