
Given:
The position–time (x–t) graph shows the motion of two children A and B starting from the school O and moving towards their homes P and Q respectively.
In an x–t graph:
(a) (A/B) lives closer to the school than (B/A)
From the graph:
Home P (for A) is lower on the position axis than home Q (for B).
So, A’s home is closer to the school than B’s home.
Correct answer: A lives closer to the school than B.
(b) (A/B) starts from the school earlier than (B/A)
From the graph:
The line for A starts from O at an earlier time than the line for B.
B starts later, as its graph begins to the right of A’s start.
Correct answer: A starts from the school earlier than B.
(c) (A/B) walks faster than (B/A)
Speed is given by the slope of the x–t graph.
The line for B is steeper than that for A.
Hence, B walks faster than A.
Correct answer: B walks faster than A.
(d) A and B reach home at the (same/different) time
From the graph:
The endpoints of both lines (at P and Q) lie on the same vertical line.
This indicates they reach their respective homes at the same time.
Correct answer: same time.
(e) (A/B) overtakes (B/A) on the road (once/twice)
Overtaking occurs where the two graphs intersect.
From the graph, the lines intersect only once.
Since B’s graph crosses A’s graph from below, B overtakes A.
Correct answer: B overtakes A once.
Final Answers Summary: