Question

The position of an object moving along the x axis is given by the equation \(x = 1 + t^2\) (\(x\) in meter and \(t\) in second). At what time will the magnitude of its displacement and velocity be equal?

• A. \(t = 1 \text{ s}\)
• B. \(t = 1.5 \text{ s}\)
• C. \(t = 3 \text{ s}\)
• D. \(t = 2 \text{ s}\)

Hint:

Always distinguish between "position" (\(x\)) and "displacement" (\(\Delta x\)). Using \(x = v\) would lead to \(1 + t^2 = 2t \implies (t-1)^2 = 0 \implies t = 1\), which is a common distractor option.

Answer 1

The Correct Option is D