Question:medium

The position and velocity of a particle executing simple harmonic motion at $t = 0$ are given by $3$ cm and $8$ cm/s respectively. If the angular frequency of the particle is $2$ rad/s then the amplitude of oscillation, in centimeters, is

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Use $A^2 = x^2 + (v/\omega)^2$ when position and velocity are known at the same instant.
Updated On: May 1, 2026
  • $3$
  • $4$
  • $5$
  • $6$
  • $8$
Show Solution

The Correct Option is C

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