Question

The population of a town increased from 1,50,000 to 2,24,500 in 11 years. The average percentage increase of population per year is:

• A. 8.75%
• B. 4.54%
• C. 4.37%
• D. 4.52%

Hint:

For "average percentage increase", use the simple arithmetic mean formula: \( \frac{\text{Total % Growth}}{\text{Years}} \), unless "Compound Annual Growth Rate" (CAGR) is explicitly requested.

Answer 1

The Correct Option is D

Strategy:

Initial Population = 1,50,000 Final Population = 2,24,500 Increase = \( 2,24,500 - 1,50,000 = 74,500 \).
\[ \text{Total %} = \frac{74,500}{1,50,000} \times 100 \] \[ \text{Total %} = \frac{745}{15} = \frac{149}{3} \approx 49.666% \]
\[ \text{Average %} = \frac{\text{Total %}}{\text{Number of Years}} = \frac{49.666}{11} \] \[ \text{Average %} \approx 4.515% \] Rounding to two decimal places gives 4.52%.