Question:medium
The population of a community on the 1st of June was recorded as 1,65,000. The total number of new cases of tuberculosis recorded from 1st January to 30th June was 22. The total registered cases of tuberculosis in the community were 220. What is the incidence of TB in this community per 10 lakh population?
The population of a community on the 1st of June was recorded as 1,65,000. The total number of new cases of tuberculosis recorded from 1st January to 30th June was 22. The total registered cases of tuberculosis in the community were 220. What is the incidence of TB in this community per 10 lakh population?
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Use only new cases over total population, then scale to 10 lakh.
Updated On: Jun 24, 2026
- 133
- 220
- 13.3
- 22
Show Solution
The Correct Option is A
Solution and Explanation
Read the wording first. The phrase new cases tells you this is an incidence problem, not prevalence. So the registered total of 220 is bait and the raw 22 is the numerator we need.
Set up a simple proportion. Out of 1,65,000 people, 22 fell newly ill with TB. We want the matching figure if the group were 10,00,000 people instead. Scale up the same ratio:
\[\frac{22}{1,65,000} = \frac{x}{10,00,000}\]
Cross multiply: $x = \dfrac{22 \times 10,00,000}{1,65,000}$. The denominator 1,65,000 goes into 10,00,000 about 6.06 times, and $22 \times 6.06 \approx 133$.
So roughly 133 new cases would arise per 10 lakh population. The value 13.3 is what you would get per 1 lakh, which is the wrong denominator, and 220 and 22 ignore the scaling entirely.
\[\boxed{\text{A. } 133 \text{ per 10 lakh}}\]
Set up a simple proportion. Out of 1,65,000 people, 22 fell newly ill with TB. We want the matching figure if the group were 10,00,000 people instead. Scale up the same ratio:
\[\frac{22}{1,65,000} = \frac{x}{10,00,000}\]
Cross multiply: $x = \dfrac{22 \times 10,00,000}{1,65,000}$. The denominator 1,65,000 goes into 10,00,000 about 6.06 times, and $22 \times 6.06 \approx 133$.
So roughly 133 new cases would arise per 10 lakh population. The value 13.3 is what you would get per 1 lakh, which is the wrong denominator, and 220 and 22 ignore the scaling entirely.
\[\boxed{\text{A. } 133 \text{ per 10 lakh}}\]
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