Question

The polar section modulus for a circular shaft of diameter "d" is:

• A. \( \frac{\pi d^3}{16} \)
• B. \( \frac{\pi d^3}{32} \)
• C. \( \frac{\pi d^3}{64} \)
• D. \( \frac{\pi d^3}{128} \)

Hint:

The polar section modulus is crucial for calculating torsional stress in shafts, and it depends on the cube of the shaft's diameter.

Answer 1

The Correct Option is A

Step 1: Polar Section Modulus Formula.
The polar section modulus, \(Z_p\), for a circular shaft is:\[Z_p = \frac{\pi d^3}{16}\]This equation is based on the circular shaft's geometry and is used to calculate torsional stress.Step 2: Summary.
For a circular shaft with diameter \( d \), the polar section modulus is \( \frac{\pi d^3}{16} \). Final Answer: \[ \boxed{\frac{\pi d^3}{16}} \]