Question:medium

The plane \(\frac{x}{2}+\frac{y}{3}+\frac{z}{4} = 1\) cuts the axes at the points A, B, C then the area of triangle ABC is

Show Hint

Find the three axis intercept points and use half the magnitude of the cross product.
Updated On: Oct 1, 2026
  • \(\sqrt{29}\)
  • \(\sqrt{41}\)
  • \(\sqrt{61}\)
  • \(\sqrt{51}\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Projection Formula:
For a triangle whose projections on the coordinate planes have areas $A_{xy},A_{yz},A_{zx}$, the area is $\sqrt{A_{xy}^2+A_{yz}^2+A_{zx}^2}$.

Step 2: Projections:
On the xy-plane the triangle projects to the triangle with legs 2 and 3: area 3. On the yz-plane, legs 3 and 4: area 6. On the zx-plane, legs 4 and 2: area 4.

Step 3: Combine:
$\sqrt{9+36+16}=\sqrt{61}$. Option (C).

Final Answer:
Option (C). \[ \boxed{\text{(C) } \sqrt{61}} \]
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