Question:medium

The plan of an area has shrink side that line originally \(20\) cm now measures \(19.5\) cm. If the original scale of plan is \(1\) cm \(= 10\) m, determine (i) correct distance to a measured distance of \(198\) m (ii) correct area corresponding to measured area of \(20000\ \text{m}^2\) Choose the correct answer from the options given below:

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For shrunk maps or plans: Linear correction: \[ \boxed{ \frac{\text{Original length}} {\text{Shrunk length}} } \] Area correction: \[ \boxed{ \left( \frac{\text{Original length}} {\text{Shrunk length}} \right)^2 } \] Remember: \[ \boxed{ \text{Area corrections always use square of linear correction} } \]
Updated On: May 26, 2026
  • (i) \(208.24\) m and (ii) \(22512.5\ \text{m}^2\)
  • (i) \(195.88\) m and (ii) \(18743.76\ \text{m}^2\)
  • (i) \(204.12\) m and (ii) \(21256.24\ \text{m}^2\)
  • (i) \(212.36\) m and (ii) \(17486.76\ \text{m}^2\)
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The Correct Option is A

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