Question

The pitch and the number of circular scale divisions in a screw gauge with least count 0.02 mm are respectively

• A. 1 mm and 100
• B. 0.5 mm and 50
• C. 1 mm and 50
• D. 0.5 mm and 100
• E. 1 mm and 200

Hint:

To quickly check, you can rearrange the formula to \( \text{Pitch} = LC \times N \). Only option (C) satisfies \( 1 = 0.02 \times 50 \).

Answer 1

The Correct Option is C