The pessimistic time and optimistic time of completion of an activity are given as 10 days and 4 days respectively. Then the variance of the activity is
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Be careful not to confuse standard deviation with variance!
- $\text{Standard Deviation} = \frac{t_p - t_o}{6}$
- $\text{Variance} = \left(\frac{t_p - t_o}{6}\right)^2$
Always make sure to square your result when a question asks for the variance.