Question:medium
The percentage hydrolysis of \( 0.15\,\text{M} \) solution of ammonium acetate.
Given: \( K_a \) for \( \text{CH}_3\text{COOH} = 1.8 \times 10^{-5} \) and \( K_b \) for \( \text{NH}_3 = 1.8 \times 10^{-5} \).
The percentage hydrolysis of \( 0.15\,\text{M} \) solution of ammonium acetate.
Given: \( K_a \) for \( \text{CH}_3\text{COOH} = 1.8 \times 10^{-5} \) and \( K_b \) for \( \text{NH}_3 = 1.8 \times 10^{-5} \).
Given: \( K_a \) for \( \text{CH}_3\text{COOH} = 1.8 \times 10^{-5} \) and \( K_b \) for \( \text{NH}_3 = 1.8 \times 10^{-5} \).
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Hydrolysis of salt of weak acid and weak base depends on Kₐ, Kb and concentration.
Updated On: Mar 23, 2026
- 0.556
- 4.72
- 9.38
- 5.56
Show Solution
The Correct Option is C
Solution and Explanation
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