Question

The oxidation states not shown by Mn in the given reaction is:
\( 3MnO_4^{2-} + 4H^+ \rightarrow 2MnO_4^- + MnO_2 + 2H_2O \)
A. +6
B. +2
C. +4
D. +7
E. +3
Choose the most appropriate answer from the options given below:

• A. D and E only
• B. B and D only
• C. A and B only
• D. B and E only

Answer 1

The Correct Option is D

We will determine the oxidation states of Mn in the reactants and products. For MnO$_4^{2-}$, let the oxidation state of Mn be $x$. Then $x + 4(-2) = -2$, yielding $x = +6$. For MnO$_4^-$, $x + 4(-2) = -1$, so $x = +7$. For MnO$_2$, $x + 2(-2) = 0$, resulting in $x = +4$. The Mn oxidation states in this reaction are +6, +7, and +4. Consequently, the oxidation states not explicitly shown are +2 and +3.