Question:easy

The oxidation number of Pt in [Pt(en)2Cl2]2+ is :

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en is neutral (0); each Cl is -1; sum of charges must equal the +2 on the ion.
Updated On: Jun 15, 2026
  • + 3
  • + 4
  • + 2
  • + 6
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The Correct Option is B

Solution and Explanation

Balance the charges on the complex ion. The two $en$ ligands are neutral and contribute $0$; the two $Cl^{-}$ contribute $2\times(-1)=-2$. Writing the metal oxidation state as $n$ and equating to the ionic charge $+2$:
\[n+(-2)=+2 \;\Rightarrow\; n=+4\]So platinum is in the $+4$ state. Correct option: (B) +4.
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