Question:medium

The oxidation number of Co in complex [Co(H$_2$NCH$_2$CHNH$_2$)$_3$]$_2$(SO$_4$)$_3$ is:

Updated On: Mar 27, 2026
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The Correct Option is B

Solution and Explanation

To ascertain the oxidation state of cobalt (Co) within the complex [Co(H2NCH2CHNH2)3]2(SO4)3, the subsequent steps are applied:

  • The complex formula [Co(H2NCH2CHNH2)3]2(SO4)3 comprises:
    • Cobalt [Co]
    • Tris(ethylenediamine) ligands [H2NCH2CHNH2]
    • Sulfate ions (SO4)
  • Ethylenediamine (en) functions as a neutral ligand, thus it does not influence the complex's net charge.
  • The sulfate ion (SO4) carries a charge of -2. With three sulfate ions present, their cumulative charge contribution amounts to 3 × (-2) = -6.
  • The complex, as a whole, is electrically neutral. Consequently, the combined charges within [Co(en)3]2 must equal +6 to counterbalance the -6 charge originating from the sulfate ions.
  • Let 'x' represent the oxidation state of a single cobalt ion. The equation, considering two cobalt centers, is formulated as:
    \(x(2) + 0 = +6\)
  • Solving for x yields:
    \(2x = 6\)
    \(x = 3\)
  • Therefore, the oxidation number of Co in this complex is determined to be \(+3\).
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