Step 1: Trace the signals:
With $A = 1$ in all four options, the NOT gate output is always 0, so the OR gate output equals the AND gate output.
Step 2: AND gate output:
$B\cdot C$ is 1 only if $B = 1$ and $C = 1$.
Step 3: Pick:
Only option (D) has both $B$ and $C$ equal to 1.
Final Answer:
Option (D) gives Y = 1.
\[ \boxed{A=1,\ B=1,\ C=1} \]