Step 1: Recall what an OR gate does.
An OR gate gives output $1$ if at least one input is $1$. It gives $0$ only when every input is $0$.
Step 2: Write the truth table.
For inputs A and B and output Y:
A=0, B=0 gives Y=0.
A=0, B=1 gives Y=1.
A=1, B=0 gives Y=1.
A=1, B=1 gives Y=1.
Step 3: Look at the rows that give 1.
The output is $1$ in three rows: when only B is $1$, when only A is $1$, and when both are $1$.
Step 4: Describe the pattern.
In all three of those rows, at least one input is $1$. That is the simple rule for an OR gate.
Step 5: Look at the row that gives 0.
The output is $0$ only when both inputs are $0$. So that case is the opposite of what we want.
Step 6: Match the wording of options.
The phrase "either or both inputs are $1$" exactly describes "at least one input is $1$".
Step 7: State the result.
The output is $1$ if either or both inputs are $1$, which is option (2).
\[ \boxed{\text{if either or both inputs are } 1} \]