Question:medium

The number of solutions of the trigonometric equation $\sin^2 x - \sin x - 2 = 0$ in the interval $[0, 2\pi]$ is:

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Always check the range constraints of trigonometric functions first. Since $-1 \le \sin x \le 1$, roots outside this interval are instantly discarded.

Updated On: May 31, 2026

$1$
$2$
$3$
$0$

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The Correct Option is A

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