Question

The number of primary isomeric alcohols of the molecular formula \(\text{C}_4\text{H}_{10}\text{O}\) is

• A. \(1\)
• B. \(2\)
• C. \(3\)
• D. \(4\)

Hint:

Butan-1-ol and 2-methylpropan-1-ol are the two primary alcohols of C4H10O.

Answer 1

The Correct Option is B

Step 1: Use the carbon skeletons:
Butane (straight chain) allows -OH at the end carbon (primary) or at an inner carbon (secondary). Isobutane (branched) allows -OH at a CH$_3$ end (primary) or on the central carbon (tertiary).

Step 2: Count primary ones:
Straight chain end: 1. Branched chain end: 1. Total 2.

Step 3: Pick:
Option B.

Final Answer:
One from each carbon skeleton gives 2 primary alcohols. \[ \boxed{\text{(B) }2} \]