Question:easy

The number of molecules present in $2.8\,g$ of nitrogen is

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Always convert grams into moles first and then multiply by Avogadro's number.
Updated On: Jun 5, 2026
  • $6.023\times10^{22}$
  • $6.023\times10^{21}$
  • $6.023\times10^{20}$
  • $6.023\times10^{23}$
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The Correct Option is A

Solution and Explanation

Step 1: Recall Avogadro's number.
One mole of any substance contains $N_A=6.023\times 10^{23}$ particles. So if we know how many moles we have, we can find the number of molecules by multiplying by this number.

Step 2: Find the molar mass of nitrogen gas.
Nitrogen gas is $\mathrm{N_2}$, made of two nitrogen atoms. Each nitrogen atom weighs about $14\,\text{g/mol}$, so $\mathrm{N_2}$ has a molar mass of $28\,\text{g/mol}$.

Step 3: Write the moles formula.
Moles are found by dividing the given mass by the molar mass. \[ n=\frac{m}{M} \] We use this to convert grams into moles.

Step 4: Plug in the numbers.
The given mass is $2.8\,\text{g}$ and the molar mass is $28\,\text{g/mol}$. \[ n=\frac{2.8}{28}=0.1\ \text{mol} \]

Step 5: Convert moles to molecules.
Multiply the moles by Avogadro's number. \[ \text{Molecules}=0.1\times 6.023\times 10^{23} \]

Step 6: Compute the final count.
Multiplying gives \[ 6.023\times 10^{22} \] molecules, which is option 1. \[ \boxed{6.023\times 10^{22}} \]
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