Question

The number of lines of force originating from a point charge of \(2\times 8.85\times 10^{-9}\) C in a medium of dielectric constant \(10\) is (\(ε_0 = 8.85\times 10^{-12}\) SI unit)

• A. \(100\)
• B. \(200\)
• C. \(400\)
• D. \(2000\)

Hint:

Divide q/epsilon0 by the dielectric constant.

Answer 1

The Correct Option is B

Step 1: Flux in vacuum:
In air, $\dfrac q{\varepsilon_0}=\dfrac{2\times8.85\times10^{-9}}{8.85\times10^{-12}}=2000$.

Step 2: In the medium:
The medium reduces the field by $K=10$, so the lines drop by the same factor: $2000/10=200$.

Step 3: Select:
Option (B).

Final Answer:
The dielectric reduces 2000 lines to 200. \[ \boxed{B} \]