To solve this problem, we need to determine the number of isoelectronic species and then calculate the number of electrons in the t
2g orbital of the complex CoCl
2(en)
2NH
3 after reacting with excess AgNO
3.
First, let's find the isoelectronic species among S
2−, C
4−, Mn
2+, Co
3+, and Fe
3+.
- The electron configuration for these ions are:
- S2− has 18 electrons (from 16 + 2)
- C4− has 10 electrons (from 6 + 4)
- Mn2+ has 23 electrons (from 25 - 2)
- Co3+ has 24 electrons (from 27 - 3)
- Fe3+ has 23 electrons (from 26 - 3)
- Isoelectronic species have the same number of electrons. Here, Mn2+ and Fe3+ each have 23 electrons.
The number of isoelectronic species
n is 2.
For the complex CoCl
2(en)
2NH
3, determine how many moles of AgCl are formed when reacting with excess AgNO
3:
- AgNO3 reacts with Cl− ions forming AgCl. Each mole of AgCl corresponds to 1 mole of Cl−.
- From the complex, we see CoCl2, meaning there are 2 Cl− ions available per complex molecule. Thus, 2 moles of AgCl are formed for every mole of CoCl2(en)2NH3.
- Therefore, n = 2 moles of AgCl confirms the number of Cl− ions and ligands.
- Co in CoCl2(en)2NH3 is in the 3+ oxidation state (Co3+).
The electron configuration of Co
3+ is [Ar]3d
6. Its d-orbital splits into t
2g and e
g in octahedral complexes:
- In low spin complexes (as with strong field ligands like en), the electron configuration for t2g is 3dt2g6eg0.
- Thus, the number of electrons in the t2g orbital is 6.
Verifying with the expected range of 6,6: the solution matches the range.
Therefore, the number of electrons in the t
2g orbital is
6.