Question

The number of gram molecules of oxygen in $6.02 \times 10^{24}$ CO molecules is

• A. 10 g molecules
• B. 5 g molecules
• C. 1 g molecule
• D. 0.5 g molecule

Answer 1

The Correct Option is B

To determine the number of gram molecules of oxygen in 6.02 \times 10^{24} CO molecules, we need to follow these steps:

1. Understand the composition of the CO molecule:
   • Each CO molecule consists of 1 carbon atom and 1 oxygen atom.
2. Calculate the number of moles of CO molecules:
   • Avogadro's number states that 1 mole of any substance contains 6.022 \times 10^{23} molecules.
   • Therefore, the number of moles of CO molecules is:
     \frac{6.02 \times 10^{24}}{6.022 \times 10^{23}} = 10 \text{ moles}
3. Determine the number of gram molecules of oxygen:
   • Each mole of CO molecules contains 1 mole of oxygen atoms.
   • Thus, 10 moles of CO molecules will have 10 moles of oxygen atoms.
   • Therefore, there are 10 g molecules of CO, which is composed of 10 g moles of oxygen atoms.
4. Relate it to the options:
   • Since 10 moles CO corresponds directly to 10 moles of Oxygen atoms.
   • However, since CO is a diatomic molecule consisting of C and O, each complete molecule is often considered individually an entity. Therefore, we need to divide by 2, leading us with 5 moles (g molecules) of dioxygen molecules.
   • Thus, the correct answer is: 5 g molecules.

This calculation shows that in 6.02 \times 10^{24} CO molecules, there are indeed 5 gram molecules of oxygen as specified in the options.