Question

The number of double bonds present in the isohypsic transformation product of allylic alcohol (Z) is _ _ _. (in integer)

Hint:

Isohypsic isomerization of allylic alcohols usually converts an alkene alcohol into an aldehyde or ketone without changing the total number of double bonds.

Answer 1

Correct Answer: 1

Step 1: Read the starting molecule.
Compound Z is an allylic alcohol, an $-OH$ sitting next to a carbon-carbon double bond. It holds one $C\!=\!C$ double bond.

Step 2: Meaning of isohypsic.
An isohypsic change is redox neutral, the overall oxidation level of carbon does not move. For an allylic alcohol this shifts the double bond and turns the $-OH$ into a carbonyl.

Step 3: Track the double bonds.
The original $C\!=\!C$ disappears, but a new $C\!=\!O$ appears in its place. One double bond out, one double bond in.

Step 4: Count in the product.
So the product still holds exactly one double bond, the carbonyl.

Step 5: Answer.
\[ \boxed{1} \]