Question

The number of atoms in $0.1$ mole of a triatomic gas is $(N_A = 6.023 \times 10^{23} \, mol ^{-1})$

• A. $ 6.026 \times 10^{22}$
• B. $ 1.806 \times 10^{23}$
• C. $ 3.600 \times 10^{23}$
• D. $ 1.800 \times 10^{22}$

Answer 1

The Correct Option is B

To determine the number of atoms in 0.1 mole of a triatomic gas, we need to follow these steps:

1. First, identify the basic concept of a triatomic gas. A triatomic gas means that each molecule of the gas contains three atoms.

2. Recall Avogadro's number, N_A = 6.023 \times 10^{23} \, mol^{-1}, which represents the number of units (atoms or molecules) in one mole of a substance.

3. Calculate the total number of molecules in 0.1 mole of the triatomic gas:

   The number of molecules = moles × Avogadro's number

   = 0.1 \, \text{mol} \times 6.023 \times 10^{23} \, \text{mol}^{-1}

   = 6.023 \times 10^{22} molecules

4. Since each molecule of a triatomic gas contains three atoms, calculate the total number of atoms:

   The number of atoms = number of molecules × number of atoms per molecule

   = 6.023 \times 10^{22} \times 3

   = 1.8069 \times 10^{23}

   Rounding this, we get approximately 1.806 \times 10^{23} atoms.

Hence, the correct answer is 1.806 \times 10^{23} atoms.