Question

The number of arrangements of the letters in the word SOLAPUR, so that consonants and vowels are placed alternately is

• A. \(100\)
• B. \(129\)
• C. \(144\)
• D. \(121\)

Hint:

SOLAPUR has 4 consonants and 3 vowels, so the pattern must be C V C V C V C.

Answer 1

The Correct Option is C

Step 1: Fix the positions
Seven positions, consonants must take the odd positions 1, 3, 5, 7.

Step 2: Count
Choose an order for S, L, P, R in those four slots: 24. Fill the remaining 3 slots with O, A, U: 6. Product 144, option (C).

Final Answer:
The count is $4!\times3! = 144$, option (C). \[ \boxed{144} \]