Question:easy

The north pole of a long horizontal bar magnet is being brought towards a closed circuit consisting of a coil. The direction of induced current produced in it is

Show Hint

Remember the visual mnemonic letters N and S with directional arrows on their tips:
The tips of the letter N point Anticlockwise ($\circlearrowleft$).
The tips of the letter S point Clockwise ($\circlearrowright$).
Since an approaching North pole induces a North polarity face to repel it, the current must flow anticlockwise!
Updated On: Jun 4, 2026
  • anticlockwise
  • horizontal
  • vertical
  • clockwise
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: The situation.
The north pole of a bar magnet is moved toward a coil. Moving a magnet near a coil makes a current flow in the coil. We must find which way this current goes.
Step 2: The guiding law.
Lenz's law tells us that the coil always fights the change being done to it. The induced current is set up to oppose whatever the magnet is trying to do. \[ \mathcal{E} = -\frac{d\Phi_B}{dt} \]
Step 3: What change is happening.
As the north pole comes closer, more magnetic field lines pass into the coil. So the magnetic flux through the coil is increasing.
Step 4: How the coil fights back.
To oppose the approaching north pole, the near face of the coil must also become a north pole. Two north poles push each other away, so the coil tries to repel the magnet.
Step 5: Find the current direction.
Use the right-hand grip rule. For the coil's face to act as a north pole, looking at that face the current must flow anticlockwise.
Step 6: State the answer.
So the induced current is anticlockwise, which is option (1). \[ \boxed{\text{Anticlockwise}} \]
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