Question:medium

The normal at the point \((1,1)\) on the curve \(2y+x^2=3\) is?

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Normal slope is the negative reciprocal of tangent slope. First differentiate to get tangent slope, then find the normal equation.

Updated On: Jun 6, 2026

\(x+y=0\)
\(x-y=0\)
\(x+y+1=0\)
\(x+y-1=0\)

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The Correct Option is B

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