The question asks us to determine the increase in temperature when a certain amount of heat is supplied to water. To solve this, we will use the formula:
q = nC\Delta T
where:
First, calculate the number of moles of water:
The molecular weight of water (H2O) is 18 g/mol.
Moles of water, n = \frac{\text{mass of water}}{\text{molar mass}} = \frac{100 \, \text{g}}{18 \, \text{g/mol}} \approx 5.56 \, \text{mol}
Now use the heat transfer formula:
The heat supplied, q = 1.0 \, \text{kJ} = 1000 \, \text{J}
Substitute the values into the formula:
1000 = 5.56 \times 75 \times \Delta T
Solve for \Delta T:
\Delta T = \frac{1000}{5.56 \times 75} \approx 2.4 \, \text{K}
Thus, the increase in temperature of the water is 2.4 K.
This matches the provided correct answer option.
A real gas within a closed chamber at \( 27^\circ \text{C} \) undergoes the cyclic process as shown in the figure. The gas obeys the equation \( PV^3 = RT \) for the path A to B. The net work done in the complete cycle is (assuming \( R = 8 \, \text{J/molK} \)):
