Question:medium

The minimum value of the function $f(x) = x^2 + \frac{250}{x}$ for $x > 0$ is:

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Alternatively, you can use the AM-GM inequality: $x^2 + \frac{125}{x} + \frac{125}{x} \ge 3\sqrt[3]{x^2 \cdot \frac{125}{x} \cdot \frac{125}{x}} = 3(25) = 75$. This avoids calculus entirely!

Updated On: May 31, 2026

$75$
$50$
$25$
$100$

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The Correct Option is A

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The minimum value of the function $f(x) = x^2 + \frac{250}{x}$ for $x > 0$ is:

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The Correct Option is A

Solution and Explanation

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