Question:medium

The maximum value of \(3\cos\theta+4\sin\theta\) is

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The maximum value of \(a\cos\theta+b\sin\theta\) is \(\sqrt{a^2+b^2}\), and the minimum value is \(-\sqrt{a^2+b^2}\).
  • \(2\)
  • \(4\)
  • \(5\)
  • \(1\)
Show Solution

The Correct Option is C

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