Question:medium

The maximum bending stress induced in a beam of rectangular section is 160 N/mm$^2$. If the depth of beam is increased by two times, keeping all the parameters same, the maximum bending stress induced in the beam is

Show Hint

For rectangular beams, the section modulus $Z$ is proportional to $d^2$.
Since bending stress $\sigma = M/Z$, the stress is inversely proportional to $d^2$.
This means doubling the depth makes the beam four times stronger in bending.
Updated On: Jul 1, 2026
  • 20 N/mm$^2$
  • 40 N/mm$^2$
  • 80 N/mm$^2$
  • 160 N/mm$^2$
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
Rectangular beam depth doubled. Initial stress 160 N/mm². Find new stress.

Step 2: Key Relationship (Alternate):
σ=6M/(bd²). So σ ∝ 1/d². Doubling depth → stress becomes 1/4.

Step 3: Detailed Explanation:
σ₂/σ₁ = (d₁/d₂)² = (1/2)² = 1/4. σ₂ = 160/4 = 40 N/mm².

Step 4: Final Answer:
New maximum bending stress is 40 N/mm².
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