The mass of benzanilide obtained from the benzoylation reaction of \(5.8 \, \text{g}\) of aniline, if yield of product is \(82%\), is ______________ g (nearest integer).
(Given molar mass in g mol\(^{-1}\): H : 1, C : 12, N : 14, O : 16)
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In yield-based problems, always calculate the theoretical yield first using stoichiometry, then multiply by percentage yield to obtain the actual product mass.
To find the mass of benzanilide obtained, follow these steps:
Calculate the moles of aniline used. The chemical formula for aniline is C6H5NH2. The molar mass of aniline is calculated as: Molar Mass of C6H5NH2 = \(6 \times 12 + 5 \times 1 + 14 + 2 \times 1 = 93 \, \text{g mol}^{-1}\).
The moles of aniline = \(\frac{5.8 \, \text{g}}{93 \, \text{g mol}^{-1}} \approx 0.0624 \, \text{mol}\).
Since the reaction of aniline with benzoyl chloride produces benzanilide, and it is a 1:1 reaction, the moles of benzanilide formed = moles of aniline = 0.0624 mol.
The molecular formula of benzanilide is C13H11NO. Its molar mass is: Molar Mass of C13H11NO = \(13 \times 12 + 11 \times 1 + 14 + 16 = 197 \, \text{g mol}^{-1}\).
Theoretical mass of benzanilide = \(0.0624 \, \text{mol} \times 197 \, \text{g mol}^{-1} = 12.293 \, \text{g}\).
Actual mass with 82% yield = \(0.82 \times 12.293 \, \text{g} \approx 10.08 \, \text{g}\).
Rounding to the nearest integer, the mass obtained is 10 g.
This result fits the range of 10,10, confirming its correctness.