Question:medium

The major product \(P\) from the following reaction is:

Show Hint

Bulky bases like \(t\)-BuO⁻ favor E2 elimination and often give the more stable conjugated alkene as the major product.
Updated On: Jun 19, 2026
  • Option 1
  • Option 2
  • Option 3
  • Option 4
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Substrate assessment.
The reactant is a benzylic tertiary bromide; such substrates strongly favor elimination because the resultant conjugated alkene is highly stabilized.

Step 2: Base characteristics.

Sodium tert-butoxide is a bulky, strong base whose steric bulk inhibits nucleophilic substitution while readily abstracting β-hydrogens.

Step 3: Reaction pathway.

An E2 mechanism operates, with the base removing a β-proton anti to the bromide leaving group, generating a double bond.

Step 4: Product determination.

Elimination yields a styrene-type conjugated alkene where the new double bond conjugates with the aromatic ring, providing maximum resonance stability.

Step 5: Stability rationale.

Conjugation with the benzene ring makes the alkene the dominant product over any substitution alternative.

Step 6: Conclusion.

The major product corresponds to option (3).
Was this answer helpful?
0