Question:medium

The major product of the reaction between CH$_3$CH$_2$ONa and (CH$_3$)$_3$CCl in ethanol is:

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Tertiary alkyl halides preferentially undergo elimination (E2) instead of substitution due to steric hindrance.
Updated On: Jan 13, 2026
  • CH$_3$CH$_2$OC(CH$_3$)$_3$
  • CH$_2$ = C(CH$_3$)$_2$
  • CH$_3$CH$_2$C(CH$_3$)$_3$
  • CH$_3$CH = CHCH$_3$
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Reaction Mechanism Analysis
The reaction involves sodium ethoxide (CH$_3$CH$_2$ONa) and tert-butyl chloride [(CH$_3$)$_3$CCl] in ethanol. Due to steric hindrance, tertiary alkyl halides favor elimination (E2) over substitution. 
Step 2: Major Product Determination 
Sodium ethoxide, a strong base, promotes elimination via the E2 mechanism, yielding an alkene. The resultant product is isobutene (\( CH_2 = C(CH_3)_2 \)). Therefore, the correct option is (B).

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