




Another way to pick the right structure is to work backward from alkene stability instead of forward from the mechanism step by step.
Acid treatment of an alcohol is a standard way to build an alkene by E1 dehydration: protonate the OH, lose water to make a carbocation, then lose an adjacent proton to form the double bond. Since the reaction runs under acidic, reversible conditions, the alkene that ends up as the major product is whichever one is the most stable, not necessarily the first one formed.
Acid-catalyzed dehydrations of polycyclic alcohols like this one are well known to proceed with skeletal (Wagner-Meerwein) rearrangement of the intermediate cation before the final proton loss, so the system can reach the most substituted, most stable alkene rather than stopping at whatever alkene sits closest to the original OH position.
Ranking the four candidates by alkene stability puts option (B) on top, which is why it is the major product formed under these acidic, thermodynamically controlled dehydration conditions.

What is a rate determining step?